Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
99 views
in Physics by (54.1k points)
closed by

The rate of flow of heat (Q), through a conductor, depends on the coefficient of thermal conductivity (σ), area of cross section (A), temperature difference across the two ends of the rod (Δθ), and the length (Δl) of the conductor. The relevant formula

\(Q=σA\frac{Δ\theta}{Δl}\)

is used to determine σ experimentally. The relative percentage errors, in the measurement of different quantities, are as follow: 

Flowing heat energy = 2% 

Time for which heat flows = 0.2% 

Temperature difference = 2% 

Length of the rod = 0.5% 

Area of cross section of the rod = 0.5%

The relative percentage error, in the determination of σ , would be

(1) 0.2%

(2) 5.2%

(3) 0.4%

(4) 2.6%

1 Answer

+1 vote
by (56.9k points)
selected by
 
Best answer

(2) 5.2%

The relation

\(Q=σA\frac{Δ\theta}{Δl}\)

can be rewritten as

\(σ=(\frac{ΔH}{Δl}).\frac{Δl}{Δ\theta}\)  \((∵Q=\frac{ΔH}{Δt})\)

∴ \(\frac{Δσ}{σ}=\frac{ΔH}{H}+\frac{Δt}{t}+\frac{Δ(Δ\theta)}{Δ\theta}+\frac{ΔA}{A}\)

= 2% + 0.2% + 0.5% + 2% + 0.5% 

= 5.2%

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...