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in Algebra by (15 points)
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Factorise 25p2−36q2

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1 Answer

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Given expression is 25p2−36q2

We notice that the expression is a difference of two perfect squares.

∴  It is in the form of a2−b2.

Hence Identity a2−b2=(a+b)(a−b) can be applied

25p2−36q2=(5p)2−(6q)2

=(5p+6q)(5p−6q)[∵a2−b2=(a+b)(a−b)]

Hence, 25p2−36q2=(5p+6q)(5p−6q)

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