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If the sum to n terms of an A.P is cn(n–1); c ≠ 0, then the sum of squares of these terms is

(a) c2n2 (n + 1)2

(b) \(\frac{2c^2}{3}n(n -1)(2n -1)\)

(c) \(\frac{2c^2}{3}n(n +1)(2n +1)\)

(d) None of these

1 Answer

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Best answer

Correct option is (b) \(\frac{2c^2}{3}n(n -1)(2n -1)\) 

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