Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.2k views
in Physics by (66.0k points)

A soap bubble is blown with the help of a mechanical pump at the mouth-of a tube the pump produces a certain increase per min in the volume of the bubble irrespective of its internal pressure the graph between the pressure inside the soap bubble and time t will be

1 Answer

+1 vote
by (71.3k points)
selected by
 
Best answer

Correct option: (A)

Explanation:

P = (4T / R) i.e. pressure inside soap bubble P ∝ (1/R)

With time t, radius of soap bubble with increase

i.e.      R ∝ t

Hence P ∝ (1/R) means P ∝ (1/t)

Hence P, t follows inverse relation hence graph is option A

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...