Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
82 views
in Parabola by (51.4k points)
closed by

The equation of the common tangents to the parabola y = x2 and y = –(x–2)2 is / are

a. y = 4(x–1)

b. y = 0

c. y = –4(x–1)

d. y = –30x – 50

1 Answer

+1 vote
by (51.1k points)
selected by
 
Best answer

Correct options are a. & b.

Let y = mx + c is tangent to y = x2

Equation of tangent are y = 0 and y = 4x–4

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...