The correct option (a) tan(x/2)
Explanation:
(1 – cosx)cose2x = cosec2x – cosx ∙ cosec2x
= cosec2x – cosecx ∙ cotx
∴ I = ∫(cosec2x – cosecxcotx)dx
= – cotx + cosecx + c
= [(– cosx + 1)/(sinx)] + c
= [(1 – cosx)/(sinx)] + c
= [{2sin2(x/2)}/{2sin(x/2) ∙ cos(x/2)}] + c
= tan(x/2) + c