Question

The temperature of sink of Carnot engine is 27°C . Efficiency of engine is 25% Then find the temperature of source. 

(A) 227° C 

(B) 327° C 

(C) 27° C 

(D) 127° C

Answer 1

Correct option: (D) 127° C

Explanation:

Given:  η = 25%

Temp of sink = T₂ = 27 °C = 300 K

As  η = 1 – (T₂ / T₁)

∴  (1/4) = 1 – [(300) / T₁]

∴ (3/4) = [(300) / T₁]

∴  T₁ = 400 K

i.e. Temp of source = 400 K = 127 °C