Question

Instantaneous voltage of the amplitude modulated wave is given by

\(\nu_{AM}=V_c(1+m\,sin\,ωt)sin\,ω_ct\)

Assuming that the effective resistance of the modulator circuit is R, the total power of the amplitude modulated wave will be equal to,

(1) \(\frac{V^2_c}{2R}\)

(2) \(\frac{m^2V^2_C}{8R}\)

(3) \(\frac{m^2V^2_C}{4R}\)

(4) \(\frac{V^2_c}{2R}[\frac{1+m^2}{2}]\)

Answer 1

(4) \(\frac{V^2_c}{2R}[\frac{1+m^2}{2}]\)

The instantaneous voltage of the amplitude modulated wave can be written as,

Power of the central carrier wave

Power of the two sidebands