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in Differentiation by (15 points)
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Find the radius of the curvature of the curve r = a sin n theta at the pole by polar form.

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\(r = asin(n\theta) \)

\(\frac {dr}{d\theta} = ancos(n\theta)\)

\(\frac {d^2r}{d\theta^2} = -an^2sin (n \theta)\)

radius of curvature

\(S = \cfrac{\{r^2 + (\frac {dr}{d\theta})^2\}}{r^2 + 2 (\frac {dr}{d\theta})^2 - r\frac{d^2r}{d\theta^2}}\)

\(= \frac {(a^2sin^2n\theta + a^2 + n^2 cos^2n\theta)^{3/2}}{a^2 sin^2n\theta + 2a^2n^2 cos^2n\theta + a^2 n^2 sin^2 n\theta}\)

\(= \frac{a^3(sin^2n\theta + n^2cos^2n\theta)^{3/2}}{a^2 (sin^2\theta + n^2sin^2n\theta + 2n^2 cos^2n\theta)}\)

\(= \frac {a(sin^2n\theta + n^2cos^2n\theta)^{3/2}}{(n^2 + 1)sin^2n\theta + 2n^2 cos^2n\theta}\)

at \(\theta = 0\)

\(= \frac {a.n^3}{2n^2}\)

\(= \frac{an} 2\)

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