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If the perimeter of a semicircular protractor is 72 cm then find its diameter.

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Perimeter of semicircular protractor = 72 cm

The formula of the perimeter of semicircle = πr + 2r, where r is the radius

According to the question,

πr + 2r = 72 cm

⇒ r(π + 2) = 72 cm

Putting the value of π as 3.14 in the sum,

⇒ r(3.14 + 2) = 72 cm

⇒ 5.14 r = 72 cm

⇒ r = \(\frac{72}{5.14}cm\)

⇒ r = 14.007 cm

We know, Diameter = 2r, where r is the radius.

∴ Diameter = 2r

= (2 × 14.007) cm

= 28.014 cm

The diameter of the semicircle protractor is 28.014 cm.

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