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\(\frac d{dx} (cos^23x) = \)

(A) 2cos3x

(B) 3sin6x

(C) -3sin6x

(D) 2sin6x

1 Answer

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Best answer

Correct option is (C) -3sin6x

\(\frac d{dx} (cos^23x) \)

\(= 2cos3x \frac d{dx} cos 3x\)

\(= -6cos 3x \, sin 3x\)

\(= -3sin 6x\)

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