Question

Two masses m₁ and m₂ are attached to the two ends of a massless spring having force constant k. When the system is in equilibrium, if the mass m₁ is detached, then the angular frequency of mass m₂ will be……….. 

(A) √(k/m₁) 

(B) √(k/m²) 

(C) √(k/m₂) + m₁ 

(D) √{k/(m₁ + m₂)}

Answer 1

The correct option (B) √(k/m²)

Explanation:

ω = √(k/m)

initially two masses are attached hence initial angular frequency

ω₁ = √{k/(m₁ + m₂)}

if mass m₁ is detached angular frequency = ω₂ = √(k/m²)