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बिन्दु \( (2,3) \) से रेखा \( 2 x-3 y+9=0 \) की सेत \( x-y+1=0 \) के अनदिश दरी ज्ञात कीजिए

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Distance of point (2, 3) from 2x - 3y + 9 = 0 is

\(d = \frac {4 - 9 + 9}{\sqrt{4 +9}} = \frac 4{\sqrt{13}} unit\)

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