​If A1 is the area bounded by 2x ≤ y ≤ √4(x - 1)^2 in 1st quadrant & A2 is the area bounded by y = min ​

Question

If A₁ is the area bounded by 2x ≤ y ≤ \(\sqrt{4(x-1)^2}\) in 1st quadrant & A₂ is the area bounded by y = min \((2x, \sqrt{4(x -1)^2})\) and x-axis. Find \(\frac{A_1}{A_2}\).

(1) 1/4

(2) 4

(3) 2

(4) 1

Answer 1

Correct option is (4) 1