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An electron accelerated through a potential difference V1 has a de-Broglie wavelength of λ. When the potential is changed to V2, its de-Broglie wavelength increases by 50%. The value of \((\frac{V_1}{V_2})\) is equal to

(1) 3 

(2) 9/4 

(3) 3/2 

(4) 4

1 Answer

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by (50.4k points)
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Best answer

Correct option is (2) 9/4 

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