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The d-electronic configuration of [CoCl4]^2– in tetrahedral crystal field is e^mt2^n. Sum of 'm' and 'number of unpaired electrons is _______.

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The d-electronic configuration of [CoCl4]2– in tetrahedral crystal field is emt2n. Sum of 'm' and 'number of unpaired electrons is _______.

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Number of unpaired electrons = 3

So, answer = 7

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