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The equation e^4x + 8e^3x + 13e^2x - 8e^x + 1 = 0, x ∈ R has 

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The equation e4x + 8e3x + 13e2x - 8ex + 1 = 0, x ∈ R has 

(1) two solutions and both are negative 

(2) no solution 

(3) four solutions two of which are negative 

(4) two solutions and only one of them is negative

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1 Answer

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(1) two solutions and both are negative

e4x + 8e3x + 13e2x - 8ex + 1 = 0

Hence two solution and both are negative.

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