Question

The distance of point P(7,4) origin.

Answer 1

I am not sure what this question is asking exactly, but....

If you asking for the distance from point (7,4) to the origin, then the answer is:

the distance = the square root of (49 + 16)

The distance is approximately 8.06 units

Answer 2

The origin is the point (0, 0) on the coordinate plane. To find the distance between the point P(7, 4) and the origin, we can use the distance formula:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

where (x₁, y₁) is the coordinates of the origin, and (x₂, y₂) is the coordinates of the point P.

Substituting the values, we get:

d = √((7 - 0)² + (4 - 0)²) = √(49 + 16) = √65 ≈ 8.06

Therefore, the distance of the point P(7, 4) from the origin is approximately 8.06 units.

Answer 3

Distance of point (7,4) from origin

\(=\sqrt{(7-0)^2+(4-0)^2}\)

\(=\sqrt{49+16}=\sqrt{65}\) unit