\(2y^2 - 4y + 4 = -3x\)
⇒ \(y^2 - 2y + 2 = \frac{-3x}2\)
⇒ \((y - 1)^2 = \frac{-3x}2 - 1= \frac{-3x -2}2\)
⇒ \((y - 1)^2 = \frac{-1}2(3x + 2)= \frac{-3}2 (x + \frac 23)\)
\(\therefore \) Vertex of parabola is \((\frac{-2}3,1)\)
\(4a = \frac 32\)
⇒ \(a = \frac 38\)
\(\therefore \) Focus = \((a, 1)=(\frac 38, 1)\)
Equation on directrix is x = a
⇒ x = \(\frac38\)