Question

Explain geometry of [Cu(NH₃)₄]⁺² on basis of hybridization.

Answer 1

[Cu(NH₃)₄]⁺²

Oxidation state of cu in [Cu(NH₃)₄]⁺² = +2

Electronic configuration of cu = [Ar] 3d¹⁰ 4s¹

Electronic configuration of cu⁺² =

Electronic configuration of cu in [Cu(NH₃)₄]⁺² 

due to influence of NH₃ ligand unpaired Electron of d-orbital shift to p. orbit. so that, one d, one s and two p-orbital Hybridized and formed four dsp² hybridized orbital. 

All four Hybridized orbital are in one plane, because of that [Cu(NH₃)₄]⁺² has square planer geometry.