Question

On the annual day of school age wise participation of students is given in the following distribution table.

Age (in years)	Less than 6	Less than 8	Less than 10	Less than 12	Less than 14	Less than 16	Less than 18
Number of Students	2	6	12	22	42	67	76

Find the median of students.

Answer 1

We convert the cumulative frequency table into depecting class intervals with their respective frequencies as given below:

n/2 = 76/2 = 38

But 38 comes under the cumulative frequency 42 and the class interval against cumulative frequency 42 is 12 – 14. So, it is the median class.

Here l = 12, f = 20, cf = 22, h = 2