Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
77 views
in Number System by (47.0k points)
closed by

Simplify : \(\cfrac{4\frac17-2\frac14}{3\frac12+1\frac17}\div \cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{5-\frac15}}}\)

(a) 0

(b) –1

(c) \(3\cfrac{1}{24}\)

(d) 1

1 Answer

+1 vote
by (52.8k points)
selected by
 
Best answer

Correct option : (d) 1

Given Exp. \(=\cfrac{\frac{29}{7}-\frac94}{\frac72+\frac87}\div \cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{\frac{24}{5}}}}\)

\(=\cfrac{\frac{116-63}{28}}{\frac{49+16}{14}}\div \cfrac{1}{2+\cfrac{1}{2+\cfrac{5}{24}}}\)

\(=\cfrac{53}{28}\times \cfrac{14}{65}\div \cfrac{1}{2+\cfrac{1}{\frac{53}{24}}}\)

\(=\cfrac{53}{28}\times \cfrac{14}{65}\div \cfrac{1}{2+\frac{24}{53}}\)

\(=\cfrac{53}{28}\times \cfrac{14}{65}\div \cfrac{1}{\frac{130}{53}}\)

\(=\cfrac{53}{28}\times \cfrac{14}{65}\div \cfrac{53}{130} =\cfrac{53}{28}\times \cfrac{14}{65}\times\cfrac{130}{53}\)

\(=\cfrac{14}{28}\times \cfrac{130}{65}= \cfrac12\times2=1.\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...