Question

12. If the lines \( \frac{x}{1}=\frac{y}{2}=\frac{z}{3}, \frac{x-1}{3}=\frac{y-2}{-1}=\frac{z-3}{4} \) and \( \frac{x+k}{3}=\frac{y-1}{2}=\frac{z-2}{h} \) are concurrent then (A) \( h=-2, k=-6 \) (B) \( h=\frac{1}{2}, k=2 \) (C) \( h=6, k=2 \) (D) \( h=2, k=\frac{1}{2} \)

Answer 1

This is a fun problem, please let me know if you would like me to write this up.

The correct answer is: (D) h = 2, k = 1/2