Given 9x^2 + 4y^2 = 36 and a point p(2√3/√7 , 6/√7) lie on ellipse.

Question

Given 9x² + 4y² = 36 and a point \(p(\frac{2\sqrt{3}}{\sqrt{7}},\frac{6}{\sqrt{7}})\) lie on ellipse. PQ is a diameter of ellipse and RS is a diameter which is perpendicular to PQ. If \(\frac{1}{PQ^2}+\frac{1}{RS^2}=\frac{p}{m}\) in simplest form then p + m is

Answer 1

Correct answer is 13/144