Question

Two identical parallel plate capacitors of capacitance C each are connected in series with a battery of emf, E as shown. If one of the capacitors is now filled with a dielectric of dielectric constant k, the amount of charge which will flow through the battery is (neglect internal resistance of the battery) 

Answer 1

Correct option  (B)  k-1/2(k + 1) CE

Explanation:

New charge on each C = (KC/k + 1)E

Change in charge on C is supplied by battery

∴  Charge supply by battery = (KC/k + 1)E - CE/2

Charge passes through battery is change supply by battery 

∴ Ans CE[k - 1/2(k + 1)]