The correct option is (D) {(2√β) / (1 + β)}.
Explanation:
(I1 / I2) = (β/1) …. given
Intensity ∝ (amplitude)2 hence
(a1 / a2) = √(I1 / I2) = √(β/1)
[(Imax) / (Imin)] = [(a1 + a2)2 / (a1 – a2)2] hence
[(Imax) / (Imin)] = [(√β + 1)2 / (√β – 1)2] .......(1)
Fringe visibility is given by V = [(Imax – Imin) / (Imax + Imin)]
From (1)
V = [{(√β + 1)2 – (√β – 1)2} / {(√β + 1)2 + (√β – 1)2}]
= [{(β + 2√β + 1) – (β – 2√β + 1)} / {(β + 2√β + 1) + (β – 2√β + 1)}]
= [(4√β) / {2(β + 1)}]
= {(2√β) / (β + 1)}