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A straight line l1 with equation x – 2y + 10 = 0 meets the circle with equation x^2 + y^2 = 100 at B

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A straight line l1 with equation x – 2y + 10 = 0 meets the circle with equation x2 + y2 = 100 at B in the first quadrant. A line through B, perpendicular to l1 cuts the y-axis at P (0, t). The value of ‘t’ is 

(A) 12 

(B) 15 

(C) 20 

(D) 25 

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1 Answer

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Best answer

Correct option (C) 20

Explanation: 

∴ y = 8 (as point lies in 1st quadrant & x = + 6) 

The line perpendicular to x – 2y + 10 =0 

passing through (6, 8) is (y – 8) = –2(x – 6) 

2x + y = 20 

It cuts the y-axis at (0, 20)

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