Question

The temperature of a gas is -50°C. To what temperature the gas should be heated so that the rms speed is increased by 3 times ?

(1) 3295°C

(2) 3097 K

(3) 223 K

(4) 669°C

Answer 1

Correct option is (1) 3295°C

= let initial speed is v

As speed is increased by 3 times so final speed become 4v

⇒ \(\frac{v}{4v}\)

= \(\sqrt\frac{223}{T}\)

T = 3568 K

So temperature in °C = 3568 - 273 = 3295°C