Question

A hydraulic automobile lift is designed to lift vehicles of mass 5000 kg. The area of cross section of the cylinder carrying the load is 250 cm² . The maximum pressure the smaller piston would have to bear is [Assume g = 10 m/s² ]

(1) 200 × 10⁺⁶ Pa 

(2) 20 × 10⁺⁶ Pa 

(3) 2 × 10⁺⁶ Pa

(4) 2 × 10⁺⁵ Pa

Answer 1

Correct option is (3) 2 × 10⁺⁶ Pa

Force = mg = 5000 g

Area of cross section = 250 cm² = 250 × 10^-4 m²