Question

Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by

(a) A, B and C

(b) B, C and F

(c) A, B and F

(d) A, C and F

Answer 1

Correct option is (b) B, C and F

Initially, each has a pack of 10 cards.

A	B	C	D	E	F
10	10	10	10	10	10

F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B

A	B	C	D	E	F
8	13	12	10	10	7

B gives 6 to D who passes on 1 to E

A	B	C	D	E	F
8	7	12	15	11	7

Total cards possessed by D and E = 15 + 11 = 26

This number is same as the total cards possessed by B, C and F.

Answer 2

Then the number of cards possessed by D and E is equal to the number of cards possessed by (b) B, C and F