Question

When the cold junction of a certain thermo-couple was maintained at 20°C, its neutral temperature was found to be 180°C, Find its temperature of inversion.

Answer 1

\(Q_n=\frac{Q_1 +Q_2}{2}\)

Here,

Q_n = 180°C ; Q_c = 20°C

\(180°=\frac{Q_1+20}{2}\)

Q_i = 360 - 20 = 340°C