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When 0.02 Faradays of electricity was passed 0.6354 g of Cu was deposited at cathode.

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When 0.02 Faradays of electricity was passed 0.6354 g of Cu was deposited at cathode. Determine the equivalent weight of copper.

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0.02 F = 0.6354 g 

1.0 F = \(\frac {0.6354} {0.02}\) = 31.77

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