Question

The number of atoms in 4.25 g of NH₃ is approximately

(a) 1 x 10²³

(b) 1.5 x 10²³

(c) 2 x 10²³

(d) 6 x 10²³

Answer 1

Correct option is (d) 6 x 10²³

No. of NH₃ molecule = \(\frac{6.02 \times 10^{23}}{17} \times 4.25 \) = \(\frac{6.02 \times 10^{23}}{4}\)

No. of atoms = \(\frac{6.02 \times 10^{23} \times 4}{4} = 6.02 \times 10^{23}\)