Question

Pick out the isoelectronic structures from the following

\(\underset I{CH_3^+} \;\;\underset {II}{H_3O^+} \;\;\underset{III}{NH_3}\;\;\underset{IV} {CH_3^-}\)

(a) I and II

(b) I and IV

(c) I and III

(d) II, III and IV

Answer 1

Correct option is (d) II, III and IV

No. of electrons present, 

I = 6 + 3 - 1 = 8

II = 3 × 1 + 8 - 1 = 10

III = 7 + 3 × 1 = 10

IV = 6 + 3 × 1 + 1 = 10