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92U235 + 0n92U236 → fission products + neutrons + 3.20 x 10-11 J.

The energy released when 1 g of 92U235 finally undergoes fission is

(a) 12.75 x 108 kJ

(b) 16.40 x 107 kJ

(c) 8.20 x 107 kJ

(d) 6.50 x 106 kJ

1 Answer

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Correct option is (c) 8.20 x 107 kJ

Energy released = \(3.2 \times 10^{-11} \times \frac{6.02 \times 10^{23}}{235} J\)

= 8.20 x 107 kJ

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