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Oxidation number of sulphur in Na2S4O6.

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Oxidation number of sulphur in Na2S4O6.

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Let the oxidation number of S = x

2 (+1) + 4(x) + 6(-2) = 0

2 + 4x - 12 = 0

4x = 12 - 2

4x = +10

x = +2.5

Oxidation number of S in Na2S4O6 is +2.5.

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