The correct answer is: (d) All the three.
When ethyl alcohol (ethanol, C2H5OH) is treated with concentrated sulfuric acid (H2SO4), it can undergo different reactions depending on the conditions and reactants present.
Here's what can happen:
1. Formation of diethyl sulfate (diethyl sulphate, (C2H5)2SO4): In the presence of concentrated sulfuric acid, ethanol can react to form diethyl sulfate. This reaction is represented as follows:
C2H5OH + H2SO4 ⟶ (C2H5)2SO4 + H2O
2. Formation of diethyl ether (ethoxyethane, C2H5OC2H5): Under certain conditions, especially at elevated temperatures, ethanol can undergo dehydration in the presence of concentrated sulfuric acid to form diethyl ether. The reaction is as follows:
2C2H5OH ⟶ C2H5OC2H5 + H2O
3. Formation of ethylene (ethene, C2H4): If the reaction conditions are more rigorous, such as higher temperatures and excess concentrated sulfuric acid, ethanol can undergo further dehydration to form ethylene. The reaction is represented as:
C2H5OH ⟶ C2H4 + H2O
So, depending on the specific conditions and reactants, all three products (diethyl sulfate, diethyl ether, and ethylene) can be formed from ethanol when treated with concentrated sulfuric acid.