Given, focal length f = 20 cm
Magnification, m = 1/3
We have to find the distance of the object from the mirror.
Since the value of m is positive, the image is virtual and erect.
This implies that the mirror is a convex mirror.
We know, m = -(v/u)
1/3 = -v/u
v = -u/3
Using the mirror formula,
1/f = 1/v + 1/u
1/20 = 1/(-u/3) + 1/u
1/20 = -3/u + 1/u
1/20 = (-3+1)/u
1/20 = -2/u
u = -2(20)
u = -40 cm
Therefore, the required object distance is 40 cm.