Correct option is (B) x = 0, y = 0
\( 3 x-5 y=0\) .....(i)
\(9 x+15 y=0\) .....(ii)
Multiplying eq (i) by 3 and eq (ii) by 1 we get,
\(\begin{aligned} 9 x-15 y =0 \\9 x+15 y =0 \\\hline 18 x =0\end{aligned}\)
\(\therefore x = 0\)
Putting the value of x in eq (i),
\(3 x-5 y =0\)
\(3 \times 0-5 y =0 \)
\(-5 y =0\)
\(y =0\)
Hence, x = 0 and y = 0.
