Question

What is the value of enthalpy change (∆H) (in kJ/mole) for given reaction-

3C(s) + Fe₃O(s) → 2Fe(s) + 3CO(g)

Given : 

2Fe(s) + 3/2 O₂(g) → Fe₂O₃(s)   ∆H° = -824 kJ/mol

C(s) + O (g) → CO(g)  ∆H° = -110 kJ/mol

Answer 1

∆H° = 3(-110) - (-824)

= -330 + 824

= 494 kJ/mole