Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
97 views
in Physics by (47.6k points)

Two vector each of magnitude A are inclined at angle θ with each other, then magnitude of resultant vector is

(1) \(A\,cos ^2 \frac {\theta}{2}\)

(2) \(2A\,cos\frac {\theta}{2}\) 

(3) \(2A \,cos \theta\)

(4) \(A\,cos \frac {\theta}{2}\)

Please log in or register to answer this question.

1 Answer

+1 vote
by (48.8k points)

(2) \(2A\,cos\frac {\theta}{2}\) 

The magnitude of resultant vector (R) \(=\sqrt {a^2 + b^2 + 2ab \,cos\theta}\)

here a = b = A

Two vector each of magnitude A are inclined at angle

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...