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+1 vote
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in Physics by (36.2k points)

A photodiode operates at wavelength of 620 nm. Find forbidden energy gap (Eg) for the diode.

(1) Eg >> 2 eV

(2) Eg ≥ 2 eV

(3) Eg < 2 eV

(4) Eg = 1 eV

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1 Answer

+1 vote
by (35.0k points)

Correct option is (2) Eg ≥ 2 eV

\(E_g = \frac{12400}{6200} = 2eV\)

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