Question

The truth table for this given circuit is:

(1) 

A	B	Y
0	0	1
0	1	1
1	0	1
1	1	0

(2) 

A	B	Y
0	0	0
0	1	1
1	0	0
1	1	1

(3) 

A	B	Y
0	0	0
0	1	0
1	0	0
1	1	1

(4) 

A	B	Y
0	0	1
0	1	0
1	0	1
1	1	0

Answer 1

The correct option is (2).

\(Y = A.B + \bar A.B\)

\(=(A + \bar A). B\)

\(Y = 1.B\)

\(Y = B\)