Question

For a certain reaction at 300K, K = 10, then \(\triangle G^\circ\) for the same reaction is –_______ \(\times 10^{-1}kJ.\) 

(Given R = 8.314 \(jK ^{-1} mol ^{-1}\))

Answer 1

Correct answer is : 57

\(\triangle G ^\circ = -RT l nK\)

= -8.314 x 300 ln (10)

= 5744.14 J/mole

\(=57.44 \times 10^{-1} \,kJ/mole\)