Correct answer is : 2
\(\varepsilon =-\frac {d\phi}{dt}\)
\(=\frac {-d\phi}{dt}(5t^2 - 36 t +1)\)
\(\varepsilon =-[10t -36]\)
Now at t = 2 sec
\(\varepsilon = -[10\times 2-36]\)
\(q =-[20-36]\)
\(\varepsilon =16\)
Now \(i = \frac {\varepsilon}{R}\)
\(i = \frac {16}{8}\)
\(\Rightarrow i = 2A\)