(1) 22.5 cm

First case \(\frac {2}{40} = \frac {X}{60} \Rightarrow X = 3 \Omega\)
In second case \(X' = \frac {2 \times 3}{2+ 3} = 1.2 \Omega\)
\(\frac {2}{l}=\frac {1.2}{100-l}\)
200 - 2l = 1.2l
\(l= \frac {200}{3.2} = 62.5 \,cm\)
Balance length changes by 22.5 cm