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In the form of \(\frac p{2^n \times 5^m}\), 0.105 can be written as

(A) \(\frac{21}{2^2 \times 5^2}\)

(B) \(\frac{21}{2^3 \times 5^3}\)

(C) \(\frac{21}{2^3 \times 5^2}\)

(D) \(\frac{21}{2 \times 5^3}\)

1 Answer

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Best answer

Correct option is (C) \(\frac{21}{2^3 \times 5^2}\)

In this case,

\(0.105=\frac{105}{1000}=\frac{21}{200}\)

Denominator is \(200=2^{3} \times 5^{2}\)

Denominator is of the form \(2^{n} \times 5^{m}\)

\(\frac{21}{2^{3} \times 5^{2}}\)

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