Correct option is (B) 0
\(\cos 38^{\circ} \cos 52^{\circ}-\sin 38^{\circ} \sin 52^{\circ}\)
\(= \cos \left(90^{\circ}-52^{\circ}\right) \cos \left(90^{\circ}-38^{\circ}\right)-\sin 38^{\circ} \sin 52^{\circ}\)
\(= \sin 52^{\circ}\sin 38^{\circ}-\sin 38^{\circ} \sin 52^{\circ} \quad[\because \cos(90^\circ - A) = \sin A]\)
\(= 0\)
