Question

The quantum number of four electrons are given below :

I. n = 4, l = 2, ml = –2, m_s = -1/2

II. n = 3, l = 2, ml = 1, m_s = +1/2

III. n = 4, l = 1, ml = 0, m_s =+1/2

IV. n = 3, l = 1, ml = 1, m_s =-1/2

The correct order of their increasing energies will be - 

(1) I < III < II < IV 

(2) IV < II < III < I 

(3) I < II < III < IV 

(4) IV < III < II < I

Answer 1

Correct option (2) IV < II < III < I

Explanation:

Higher the value of (n + l) 

Higher will be energy of orbital. If (n + l) are equal, then higher the value n higher will be energy