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Evaluate lim x ->(cosx)1/x2 by L Hospital's rule.

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\(L = \lim\limits_{x \to 0} (\cos x)^{\frac 1{x^2}}\)

\(\log L = \frac 1{x^2} \log \cos x\)

\(\log L = \frac {\log \cos x}{x^2}\)

Using L−Hospital rule,

\(\log L = \frac{- \frac {\sin x}{\cos x}}{2x} = \frac {-\tan x}{2x}\)

Again L−Hospital rule,

\(\log L = \frac{- \sec^2x}{2} = \frac {-1}{2}\)

\(L = e^\frac 12\Rightarrow \frac 1{\sqrt e}\)

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